Question

Factorize using appropriate identity:
(a) 64xspuer+ 16x +1​

Answer 1

Step-by-step explanation:

64x²+16x+1

(8x)²+(1)²+2(8x)(1)

(8x+1)²

(8x+1)(8x+1)

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Answer 2

Answer:

heya mate ☺

$64x ^{2} + 16x + 1 = 0 \\ = > 64x ^{2} + (8 + 8)x + 1 = 0 \\ = > 64x ^{2} + 8x + 8x + 1 = 0 \\ = > 8x(8x + 1) + 1(8x + 1) = 0 \\ = > (8x + 1)(8x + 1) = 0 \\ either \: 8x + 1 = 0 \\ = > 8x = - 1 \\ = > x = - 1 \div 8 \\ or \: 8x + 1 = 0 \\ = > 8x = - 1 \\ = > x = - 1 \div 8$

⭐ hope it helps u ⭐

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