factorize using complex numbers
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Given Equation is a^2 + 1
The given equation can be written as a^2 + 1^2
= > we know that i^2 = -1.
Therefore, the given equation can be written as :
= > a^2 + 1^2
= > a^2 - i^2 [a^2 - b^2 = (a + b)(a - b)]
= > (a + i)(a - i)
Hope this helps!
Answered by
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Factorization with Complex numbers is:
Ans: a^2+1=0
a^2= -1
a= + (or) - i
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