Question

factorize using identies
2a5-32a

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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2a^5 - 32a

• Taking 2a common in both -

2a (a⁴ - 16)

= 2a [(a²)² - (4)²]

• Using identity : a² - b² = (a + b)(a -b)

= 2a [ (a² + 4)(a² - 4) ]

= 2a [ {a² + 4} {(a)² - (2)²}]

• Again using identity : a² - b² = (a + b)(a - b)

= 2a [ {a² + 4} {(a + 2) (a - 2)} ]

= 2a [(a² + 4)(a + 2)(a - 2)]

$<marquee>Hence, your answer is [2a (a² + 4)(a + 2)(a - 2)].</marquee>$
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Thank you.. ;-)

Answer 2

Answer:

Step-by-step explanation: