Question

factorize using identities
(a) 36a2 + 132ab + 121b2
​

Answer 1

Answer:

(6a+11b) ^2.........

Answer 2

Answer:

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Step-by-step explanation:

((36 • (a2)) + 132ab) + 112b2

STEP

2

:

Equation at the end of step

2

:

((22•32a2) + 132ab) + 112b2

STEP

3

:

Trying to factor a multi variable polynomial

3.1 Factoring 36a2 + 132ab + 121b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (6a + 11b)•(6a + 11b)

Detecting a perfect square :

3.2 36a2 +132ab +121b2 is a perfect square

It factors into (6a+11b)•(6a+11b)

which is another way of writing (6a+11b)2

Final result :

(6a + 11b)2