Question

factorize using identities
(a+3c)²-1​

Answer 1

(a + 3c)² - 1

(a + 3c) ² - (1)²

(a + 3c + 1 ) (a + 3c - 1 )

Answer 2

Answer:

HERE IS YOUR ANSWER...

Step-by-step explanation:

= (a+3c)^2-1

By using identity: (a+b)^2=a^2 +2ab+b^2

= (a)^2+2(a)(3c)+(3c)^2 -1

= a^2+6ac+9c^2 -1

ANSWER: a^2+6ac+9c^2 -1

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