Question

Factorize using identities
$p {2} - 20p + 100$

Answer 1

p² - 20p + 100

=> p² - 10p - 10p + 100 [Here, we have to find the factors of 100, so that the answer of additoon comes as middle term and answer of multiplication comes as last term]

=> p(p - 10) - 10(p - 10)

=> (p - 10) (p - 10)

$\therefore{p^{2} \: - \: 20p \: + \: 100 \: = \: (p \: - \: 10) \: (p \: - \: 10)}$

Answer 2

hey mate! here's your answer!

since , we have to do this by MIDDLE TERM SPLITTING method.

so, p² - 20p + 100

= p² + (-10p - 10p) + 100

= p² - 10p - 10p + 100

= p(p-10) - 10(p-10)

= (p-10)(p-10) ....ANS

HOPE YOU UNDERSTOOD!