Question

factorize using identity 1.) 16c²-1 2.)1 - 64b²

please tell me fast
please do in Notebook​

Answer 1

1. 16c²-1

= (4c)²-(1)²

= (4c + 1) (4c - 1)

2. 1 - 64b²

= (1)²-(8b)²

= (1 - 8b) (1 + 8b)

Algebraic identity used :

a²-b² = (a+b) (a-b)

Answer 2

Answer:

answer for the given problem is given