Question

factorize using identity:4m⁴+1​

Answer 1

Answer:

(2m^2+1)^2

(a+b)^2== a^2+2ab+b^2

solve this by this identity

hope it helps

Answer 2

Step-by-step explanation:

(2m^2)^2+(1)^2+4m^2-4m^2

by using identity:

(a+b)^2=a^2+b^2+2ab

(2m^2+1)^2-4m^2

(2m^2+1)^2-(2m)^2

(2m^2+1+2m)(2m^2+1-2m)