Question

factorize using identity: a³+b³- 8c³+6abc

Answer 1

Step-by-step explanation:

    remember this,

a³+b³+c³+3abc = (a +b+c)(a²+b²+c² -ab-bc-ca)

   from the given expression , a = a, b= b , c= -2c

        now put the values to get the factorized form

         hope it help and mark me as brilliant

Answer 2

Answer:

a3+b3-8c3+6abc=(a+b-2c)(a2+b2+4c2-ab+2bc+2ac)

Hope this answer help you....