Question

factorize using suitable identities
1. 9a^2 - 4b^2 - 6a + 1

Answer 1

$9a {}^{2} - 4b { }^{2} - 6a + 1 \\ = (9a {}^{2} - 6a + 1) - 4b { }^{2} \\ = (3a - 1) {}^{2} - 4b {}^{2} \\ = (3a - 1) {}^{2} - (2b) {}^{2} \\ = (3a - 1 - 2b) {}^{2} \\ = (3a - 1 - 2b)(3a - 1 - 2b)$