Question

factorize using suitable identities x^8 - y^8

Answer 1

Tjis uses the identity ----   a3 - b3  = ( a - b ) ( a2 - ab -b2 )
                                                             

x8 -y8 = ( x2 -y2 ) ( x4 - x2y2 -y4 )      [ To understand this better we will take a as x2 because x2's cube is x8 and    .                                                                b    as y8because y2's cube is y8 ] 

HOPE THIS HELPS

Answer 2

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HEY, FRIEND! HERE IS YOUR ANSWER.
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${x}^{8} - {y}^{8} \\ = ( {x}^{4} + {y}^{4} )( {x}^{4} - {y}^{4} ) \\ = ( {x}^{4} + {y}^{4} )( {x}^{2} + {y}^{2} )( {x}^{2} - {y}^{2} ) \\ = ( {x}^{4} + {y}^{4} )( {x}^{2} + {y}^{2} )(x + y)(x - y)$


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I HOPE THAT THIS HELPS YOU.
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