factorize using the splitting the middle term
x^2-11x+9
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x²-11x+9=0
comparing them above equation with
ax²+bx+c=0
therefore, a=1, b=-11 and c=9
therefore third term=[b/2]²
=(-11/2) ²
=121/4
therefore, x²-11x+121/4-121/4+9=0
(x-11/2) ²-121/4+9=0
(x-11/2) ²-121+36/9=0
(x-11/2) ²-85/9=0
(x-11/2) ²=85/9
(x±11/2) ²=85/9
x±11/2=√85\√9
x±11/2=√85/3
x=√85/3+11/2 or √85/3-11/2
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