Question

factorize (vi) y2 - 2y - 8 ​

Answer 1

Answer:

$y^2 - 2y - 8 = ( y -4)(y + 2)$

Step-by-step explanation:

First, find the two numbers whose multiplication is -8 and sum is -2

SO, the number is -4 and 2

Hence given equation can be written as

$y^2 - 2y - 8 \\= y^2 - 4y + 2y - 8\\= y ( y - 4) + 2 (y -4)\\= ( y -4)(y + 2)$

Answer 2

We can simply solve this problem with the following steps:

So y=2 or y= -4