factorize with suitable identity
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x^2-y^2+6y-9
x^2-(y+3)^2
(x+y-3)(x-y+3)
hope it helps u
x^2-(y+3)^2
(x+y-3)(x-y+3)
hope it helps u
saksham2305:
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Hello, you have made a mistake in the last step. Please correct your answer
Answered by
1
x² - y² + 6y - 9
[Take minus sign common after x²]
= x² - (y² - 6y + 9)
[ Now, we can see a perfect square.
a² - 2ab + b² = (a-b)² .
Here, a = y, b=3]
= x² - (y - 3)²
[ Now, a² - b² = (a+b)(a-b) ]
= (x + (y-3)) (x - (y-3))
= (x + y - 3)(x - y + 3)
[Take minus sign common after x²]
= x² - (y² - 6y + 9)
[ Now, we can see a perfect square.
a² - 2ab + b² = (a-b)² .
Here, a = y, b=3]
= x² - (y - 3)²
[ Now, a² - b² = (a+b)(a-b) ]
= (x + (y-3)) (x - (y-3))
= (x + y - 3)(x - y + 3)
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