factorize:x-1-(x-1)^2+ax-a
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Answered by
0
Answer:
Step-by-step explanation:
x-1-(x-1)^2+a(x-1) =0
taking x-1 common
x-1(1-(x-1)+a)=0
So
x=1
or
1-x+1+a=0
2-x+a=0
x= 2+a
Answered by
1
Step-by-step explanation:
x-1 - (x-1)^2 + ax - a
(x-1) - (x-1)^2 + a (x-1)
(x-1) (1-(x-1))^2 + a (x-1)
(x-1) (1-x+1+a)
(x-1) (2-x+a)
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