Math, asked by atreya88, 11 months ago

factorize:x-1-(x-1)^2+ax-a​
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Answers

Answered by superprem
0

Answer:

Step-by-step explanation:

x-1-(x-1)^2+a(x-1) =0

taking x-1 common

x-1(1-(x-1)+a)=0

So

x=1

or

1-x+1+a=0

2-x+a=0

x= 2+a

Answered by prataprathor2008
1

Step-by-step explanation:

x-1 - (x-1)^2 + ax - a

(x-1) - (x-1)^2 + a (x-1)

(x-1) (1-(x-1))^2 + a (x-1)

(x-1) (1-x+1+a)

(x-1) (2-x+a)

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