factorize :
x+1/x-1 = 3x-7/2x-5
Answers
Step-by-step explanation:
Hello mate.
Thanks for asking this question.
Your answer is =>
as we have given the equation =>
=>\frac{(x-1) }{(x+1) }=\frac{(2x-5) }{(3x-7) }
cross multiply both sides , we get =>
=>(X-1) (3x-7) =(2x-5) (x+1)
=>3x^{2}-7x-3x+7\: =\: 2x^{2}-3x-12
=>3x^{2}-10x+7\: =\: 2x^{2}-3x-12
=>3x^{2}-2x^{2}-10x+3x+7+5=0
=>x^{2}-7x+12\:=\:0
=>x^{2}-3x-4x+12=0
=>x(x-3) \: -\:4(x-3) =\: 0
=>(x-3) (x-4) =0
=>(x-3) =0 \: \: \: \: or\: \: \: \: (x-4) =0
=>x\: =\: 3 \: \: \: or\: \: \: x\: =\: 4
our factors for given equation are 3 & 4.
says thanks bro for this problem
Answer:
the factors are 3 and 4.
Step-by-step explanation:
x+1/x-1=3x-7/2x-5
(x+1)(2x-5)=(3x-7)(x-1)
2x²-5x+2x-5=3x²-3x-7x+7
2x²-3x-5=3x²-10x+7
x²-7x+12=0
x²-3x-4x+12=0
x(x-3)-4(x-3)=0
(x-3)(x-4)=0
Please mark this answer as brainliest.