factorize (x + 1 ) *(x + 2)*(x+3)*(x+4) -3
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(x+1)*(x+4)*(x+2)(x+3 )-3
=(x^2+5x+4)(x^2+5x+6)-3
let x^2+5x=m
so (m+4)(m+6)-3
=m^2+10m+24-3
=m^2+10m+21
=m^2+7m+3m+21
=m (m+7)+3 (m+7)
=(m+7)(m+3)
=(x^2+5x+7)(x^2+5x+3)
=(x^2+5x+4)(x^2+5x+6)-3
let x^2+5x=m
so (m+4)(m+6)-3
=m^2+10m+24-3
=m^2+10m+21
=m^2+7m+3m+21
=m (m+7)+3 (m+7)
=(m+7)(m+3)
=(x^2+5x+7)(x^2+5x+3)
kanikag:
How to solve if pairing is done (x+1) and (x+2)
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Your answer is in the Attachment
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