Question

factorize (x + 1) (x + 2) (x + 3) (x + 4) – 8

Answer 1

Answer:

(x+1)(x+2)(x+3)(x+4)-8

=(x+1)(x+4)(x+2)(x+3)-8

=(x^2+5x+4)(x^2+5x+6)-8

let x^2+5x=a

then,

(a+4)(a+6)-8

=a^2+10a+24-8

=a^2+10a+16

=a^2+8a+2a+16

=a(a+8)+2(a+8)

=(a+8)(a+2)

putting the value of a=x^2+5x

(x^2+5x+8)(x^2+5x+2)