factorize (x + 1) (x + 2) (x + 3) (x + 4) – 8
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Answer:
(x+1)(x+2)(x+3)(x+4)-8
=(x+1)(x+4)(x+2)(x+3)-8
=(x^2+5x+4)(x^2+5x+6)-8
let x^2+5x=a
then,
(a+4)(a+6)-8
=a^2+10a+24-8
=a^2+10a+16
=a^2+8a+2a+16
=a(a+8)+2(a+8)
=(a+8)(a+2)
putting the value of a=x^2+5x
(x^2+5x+8)(x^2+5x+2)
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