factorize (x^2-2x)^2-2(x^2-2x)-3
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Step-by-step explanation:
(x²-2x)²-2(x²-2x)-3
= let (x²-2x) be y
= y²-2y-3
= y²-3y+y-3
= y(y-3)+1(y-3)
= (y-3) (y+1)
now putting the value of y =(x²-2x)
{(x²-2x)-3} {(x²-2x)+1}
hope it is helpful to you
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Answer:
it is the correct answer ❤️
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