Math, asked by seemaagni8, 7 months ago

Factorize x^2+√2x-24

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Answered by rafiazafar40
0

Answer:

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Answered by ravisimsim
1

The first term is,  x2  its coefficient is  1 .

The middle term is,  √2x  its coefficient is  √2 .

The last term, "the constant", is  -24 .

Multiply the coefficient of the first term by the constant .

So,1×-24=-24.

Find the factors of -24 whose sum = √2 .

The sum of( -3√2+4√2=0). And their product is -24.

Rewrite the polynomial splitting the middle term using the two factors found above.

x^2 -3√2x+4√2x-24=0

x(x-3√2) 4√2(x-3√2)=0

(x+4√2)(x-3√2)=0.

x+4√2=0 (or) x-3√2=0

x=-4√2 (or) x=3√2.

Therefore -4√2 and 3√2 are the roots of the x^2+√2x-24.

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