Question

factorize x^2-2x-8 and verify relationship between zeroes and coefficients. ​

Answer 1

Answer:

x² - 2x -8

by splitting the middle term

x² -4x +2x -8

x(x-4) +2(x-4)

(x+2)(x-4)

x+2=0. x-4=0

x=-2. x=4

sum of zeroes =-b/a

-2+4=-(-2)/1

2=2

product of zeroes=c/a

-2*4=-8/1

-8=-8