Question

factorize (x^2+4)-2a-a^2-5​

Answer 1

Step-by-step explanation:

$( {x}^{2} + 4) - 2a - {a}^{2} - 5 \\ on \: simplifying \: we \: find \\ {x}^{2} + 4 - {a}^{2} - 2a - 5 \\ = {x}^{2} - {a}^{2} - 2a - 1 \\ = {x}^{2} - ( {a}^{2} + 2a + 1) \\ = {x}^{2} - ( {a + 1})^{2} \\ = (x + a + 1)(x - a - 1) \: are \: the \: \\ required \: factors \: of \: \\ given \: quadratic \: polynomial.$