factorize x^2-4x+1 to find their zeroes
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a = 1 , b = -4 , c = 1
b^2 - 4ac
-4^2 - 4(1)(1)
16 - 4
12
D = 12
-b +/- underroot D ÷ 2a
-(-4) + under root 12 / 2
x = 4 + underroot 12 / 2
-(-4) - underroot12 / 2
4 - underroot12/2
so the zeroes of polynomial is
( 4 + underroot12 / 2) , (4 - underrroot12 / 2)
HOPE ITS HELP...
THNks...good luck☺
b^2 - 4ac
-4^2 - 4(1)(1)
16 - 4
12
D = 12
-b +/- underroot D ÷ 2a
-(-4) + under root 12 / 2
x = 4 + underroot 12 / 2
-(-4) - underroot12 / 2
4 - underroot12/2
so the zeroes of polynomial is
( 4 + underroot12 / 2) , (4 - underrroot12 / 2)
HOPE ITS HELP...
THNks...good luck☺
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