Question

Factorize: (x+3)^2-4(x+3)-5=0​

Answer 1

Step-by-step explanation:

formula used (a+b)^2 = (a^2+b^2+2ab)

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Answer 2

Answer:

$(x + 3) {}^{2} - 4(x + 3) - 5 = 0 \\ \\ x {}^{2} + 6x + 9 - 4x - 12 - 5 = 0 \\ \\ x {}^{2} + 2x - 8 = 0 \\ \\ x {}^{2} + 4x - 2x - 8 = 0 \\ \\ x(x + 4) - 2(x + 4) = 0 \\ \\ (x + 4)(x - 2) = 0 \\ \\ x = - 4 \\ x = 2$

Step-by-step explanation:

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