Question

Factorize x^3-23x^2+142x-120

Answer 1

hope it helps.. ........

Answer 2

Answer:

$x^3-23x^2+142x-120=(x-1)(x-12)(x-10)$

Step-by-step explanation:

Given : Expression $x^3-23x^2+142x-120$

To find : Factorise the given expression?

Solution:

To factorize the given expression equate it to zero.

$x^3-23x^2+142x-120=0$

$x^3-x^2-22x^2+22x+120x-120=0$

$x^2(x-1) -22x(x-1) +120(x-1)=0$

$(x-1)(x^2-22x+120)=0$

$(x-1)(x^2-12x-10x+120)=0$

$(x-1)(x(x-12)-10(x-12))=0$

$(x-1)(x-12)(x-10)=0$

Factorize form of the given expression is $x^3-23x^2+142x-120=(x-1)(x-12)(x-10)$