factorize x^3 – 3x^2 – 9x – 5
Answers
Answered by
2059
x³ - 3x² - 9x - 5
= x³ + x² - 4x² - 4x - 5x - 5
= x²( x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1)(x² - 4x - 5)
= (x + 1)(x² -5x + x - 5)
= (x + 1)(x - 5) (x + 1)
hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .
= x³ + x² - 4x² - 4x - 5x - 5
= x²( x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1)(x² - 4x - 5)
= (x + 1)(x² -5x + x - 5)
= (x + 1)(x - 5) (x + 1)
hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .
Answered by
638
Answer: (x + 1) (x - 5) (x + 1)
Step-by-step explanation:
x³ - 3x² - 9x - 5
= x³ + x² - 4x² - 4x - 5x - 5
= x²( x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1)(x² - 4x - 5)
= (x + 1)(x² -5x + x - 5)
= (x + 1)(x - 5) (x + 1)
Hence, (x +1), (x -5) and (x +1) are the factors of given polynomial.
Similar questions