factorize x^3+7x^2+14x+5
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Answer:
Step-by-step explanation:
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((x3) - 7x2) - 14x) - 5 = 0
Step 2 :
Checking for a perfect cube :
2.1 x3-7x2-14x-5 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: x3-7x2-14x-5
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -14x-5
Group 2: -7x2+x3
Pull out from each group separately :
Group 1: (14x+5) • (-1)
Group 2: (x-7) • (x2)
anshu437351:
can you explain
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