factorize
x^3+8y^3+27z^3-18xy^2
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Hey ,
x³+8y³+27z³-18xyz
[ we know x³+y³+z³-3xyz = (x+y+z) (x²+y²+z²-xy-yz-xz]
= (x)³+(2y)³+(3z)³-3.x.2y.3z
= (x+2y+3z)(x²+4y²+9z²-2xy-6yz-3xz)
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0
Answer:
Hey ,
x³+8y³+27z³-18xyz
[ we know x³+y³+z³-3xyz = (x+y+z) (x²+y²+z²-xy-yz-xz]
= (x)³+(2y)³+(3z)³-3.x.2y.3z
= (x+2y+3z)(x²+4y²+9z²-2xy-6yz-3xz)
Step-by-step explanation:
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