Question

Factorize x^3 - 8y^3 + 27z^3 + 18xyz.

Answer 1

Hi ,

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We know the algebraic identity :

a³+b³+c³ - 3abc

= (a+b+c)(a²+b²+c²-ab-bc-ca )

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Here ,

x³ - 8y³ + 27z³ + 18xyz

= x³ + ( -2y )³ + ( 3z )³ - 3 × x ( -2y )(3z)

= [x-2y+3z][x²+(-2y)²+(3z)²-x(-2y)-(-2y)(3z)-(3zx)]

= (x-2y+3z)(x² + 4y² + 9z² + 2xy+ 6yz- 3zx )

I hope this helps you.

: )

Answer 2

Heya! !
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