Question

Factorize:

x^3-9x^2+23x-15

Plzzzzz...​

Answer 1

Answer:

solution of the given question is above

Answer 2

Answer:

p(x)= x^3-9x^2+23x-15

let us try with, p(5)

p(5)= 5^3-9×5^2+23×5-15

= 125-225+115-15= 0

so (x-5) is a factor of p(x)

by hit and trial method we get:-

x^2(x-5)-4x(x-5)+3(x-5) is a factor of p(x)

[(x^2-4x+3)(x-5)] are factors of p(x)

(x^2-3x-x+3)(x-5) are factors of p(x)

{x(x-3)-1(x-3)}(x-5) are factors of p(x)

(x-1)(x-3)(x-5) are factors of p(x).

hope it helps you

please mark brainliest