Question

Factorize `(x-3y)^(3)+(3y-7z)^(3)+(7z-x)^(3)​

Answer 1

Step-by-step explanation:

(x-3y)³+(3y-7z)³+(7z-x)³

let x-3y=a

3y-7z=b

7z-x=c

on adding

a+b+c= x-3y+3y-7z+7z-x

a+b+c= 0

we know that if a+b+c=0

then a³+b³+c³=3abc

here,

(x-3y)+(3y-7z)+(7z-x)=0

so

(x-3y)³+(3y-7z)³+(7z-x)³= 3(x-3y)(3y-7)

(7z-x)

.....666.....

Answer 2

here is your answer in the attachment bestie !♡♡♡♡

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