Question

factorize x^4-2x^3-7x^2+8x+12 plzzz fast

Answer 1

❤️HELLO!!❤️

Therefore, three zeros are −

1,

2 and −2

andfourth zero would be 12−1⋅2⋅−2=3

. Let us check it.

If a=

3 then P(x)

=1⋅34−2⋅33−7⋅32+8⋅3+12

=81−54-63+24+12=0

Answer 2

Answer:

  x⁴-2x³-7x²+8x+12

= x⁴-3x³+x³-3x²-4x²+12x-4x+12

= x³(x-3)+x²(x-3)-4x(x-3)-4(x-3)

= (x-3)(x³+2x²-x²-2x-2x-4)

= (x-3)[x²(x+2)-x(x+2)-2(x+2)]

= (x-3)(x+2)(x²-x-2)

= (x-3)(x+2)(x²+x-2x-2)

= (x-3)(x+2)[x(x+1)-2(x+1)]

= (x-3)(x+2)(x+1)(x-2)   Ans.

Step-by-step explanation:

HOPE THIS HELPS U.