Question

factorize x power of 3 - 3x power of 2 -9x - 5​

Answer 1

Step-by-step explanation:

x³ - 3x² - 9x - 5

= x³ + x² - 4x² - 4x - 5x - 5

= x²( x + 1) - 4x ( x + 1) - 5(x + 1)

= (x + 1)(x² - 4x - 5)

= (x + 1)(x² -5x + x - 5)

= (x + 1)(x - 5) (x + 1)

Hence, (x +1), (x -5) and (x +1) are the factors of given polynomial.

Answer 2

Answer:

x³-3x²-9x-5

lets try with x+1 as a factor

x+1=0

x=-1

(-1)³-3(-1)²-9(-1)-5

= -1-3+9-5

= -9+9 = 0

since we get 0, (x+1) is a factor

Now by long division method when we divide

(x³-3x²-9x-5) and (x+1)

we get

(x²-4x-5)

now let's factorize this expression using factorization method.

(x²-4x-5)

can be written as

x²+x-5x-5

let's take common terms now,

x(x+1)-5(x+1)

THE FACTORS ARE (x-5)(x+1)

The factors are/The answer you wanted is

(x+1)(x+1)(x-5)

Tada!You got your answer