factorize -- x square + 1/x square -2-3x +3/x
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Hi friend,
x²+1/x²-2-3x+3/x
→ {x²+(1/x)²-2(x)(1/x)} -3x+3/x
→ (x-1/x)²-3x+3/x
→ (x-1/x)²-3(x-1/x)
→ (x-1/x)(x-1/x)-3(x-1/x)
→ (x-1/x)(x-1/x-3)
Hope it helps
x²+1/x²-2-3x+3/x
→ {x²+(1/x)²-2(x)(1/x)} -3x+3/x
→ (x-1/x)²-3x+3/x
→ (x-1/x)²-3(x-1/x)
→ (x-1/x)(x-1/x)-3(x-1/x)
→ (x-1/x)(x-1/x-3)
Hope it helps
Answered by
4
hope this will help you
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