Factorize x Square +1/x Square +2x-2/x
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3
Given equation is incorrect. There can be no exact answer of the given Quadratic Equation.
Correct equation will be,
x² + 1/x² - 2x - 2/x + 2
Now, Solving this,
x² + 1/x² + 2 - 2x - 2/x
= [x² + 1/x² + 2] - 2[x + 1/x]
= [x + 1/x]² - 2[x + 1/x]
(∵ [x² + 1/x² + 2] can be written as [x + 1/x]²)
= [x + 1/x][ x + 1/x - 2]
The Required solution of the above Quadratic Equation will be ⇒
[x + 1/x][ x + 1/x - 2]
Hope it helps.
Correct equation will be,
x² + 1/x² - 2x - 2/x + 2
Now, Solving this,
x² + 1/x² + 2 - 2x - 2/x
= [x² + 1/x² + 2] - 2[x + 1/x]
= [x + 1/x]² - 2[x + 1/x]
(∵ [x² + 1/x² + 2] can be written as [x + 1/x]²)
= [x + 1/x][ x + 1/x - 2]
The Required solution of the above Quadratic Equation will be ⇒
[x + 1/x][ x + 1/x - 2]
Hope it helps.
Answered by
0
x²+1/x²+2x-2/x
(x²+1/x²-2) + (x-1/x) + 2
(x-1/x)² + (x-1/x) + 2
(x-1/x)(x-1/x+1)+2
The given equation cannot be factorized any further.
If the equation was x²-1/x²+2x-2/x, it could be factorized.
(x-1/x)(x+1/x) + 2(x-1/x)
(x-1/x)(x+1/x+2)
(x²+1/x²-2) + (x-1/x) + 2
(x-1/x)² + (x-1/x) + 2
(x-1/x)(x-1/x+1)+2
The given equation cannot be factorized any further.
If the equation was x²-1/x²+2x-2/x, it could be factorized.
(x-1/x)(x+1/x) + 2(x-1/x)
(x-1/x)(x+1/x+2)
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