Factorize x square + 3 root 3 x + 6
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We have, x²+3√3x+6=x²+(√3+2√3)x+6 (√3+2√3 =3√3 and (√3)(2√3)=6 )
=x²+√3x+2√3x+(√3)(2√3)
={x 2+3x}+{2√3x+(√3)(2√3)}
=x(x+√3)+2√3(x+√3)
=(x+ √3 )(x+2√3 )
∴x²+3√3x+6=(x+√3)(x+2√3)
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