factorize x square-y square-4x-2y+3
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Answer:
(a+b)3+(a−b)3=[a3+b3+3ab(a+b)]+[a3−b3−3ab(a−b)]
=2(a3+3ab2)
Therefore,
(4x+2y)3+(4x−2y)3=2[(4x)3+3×4x×(2y)2]
=2(64x3+48xy2)
=128x3+96xy2
Step-by-step explanation:
Suno tum square ko sahi se likha Kro samjhi it not square it be written as ( ²)
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