factorize (x+y)^3-(x-y)^3
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Answer :-
2y(3x² + y²)
Solution :-
(x + y)³ - (x - y)³
We know that
a³ - b³ = (a - b)(a² + ab + b³
Here
• a = x + y
• b = x - y
By substituting the values in the RHS of the identity
= {x + y - (x - y)}{(x + y)² + (x + y)(x - y) + (x - y)²}
= (x + y - x + y){x² + y² + 2xy + (x² - y²) + (x² + y² - 2xy)}
[ Identities used :-
• (x + y)² = x² + y² + 2xy
• (x - y)² = x² + y² - 2xy
• (x + y)(x - y) = x² - y² ]
= (2y)(x² + y² + 2xy + x² - y²+ x² + y² - 2xy)
= 2y(3x² + y²)
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