Question

​factorize (x+y)cube-x-y

Answer 1

@

(x+y)³-x-y
=> (x+y)³ - (x+y)
=> (x+y) [ (x+y)²-1 ]
=> (x+y) [ (x+y)²-1² ]
=> (x+y) (x+y+1) (x+y-1) Ans

@:-)

Answer 2

Hi bhai

here is your answer

Given

( x + y )³ - x - y

= ( x + y )³ - 1 ( x + y )

here x + y is common so we can write,

= ( x + y ) [ ( x + y )² - 1 ]

= ( x + y ) [ ( x + y + 1 ) ( x + y - 1 )

[ because a² - b² = ( a + b ) ( a - b )

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