factorize x²+1/x²+2-3x-3/x
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(a) x2-3x+2=x2-2x-x+23DX(x-2)+1(x-2)-(x+1) (x-2) (b) Since x2-3x+k can be written as the product of two first degree polynomials, b2-4ac=0 (3)2-4(1)(k)=0=9-4k=0 k=9/4
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