Question

factorize x²-18x+56​

Answer 1

Answer:

The factors of $x^{2} -18x+56$ is $(x-14)\ and\ (x-4)$.

Step-by-step explanation:

This is a quadratic equation with $a=1,\ b=-18,\ c=56$  , an equation is said to be quadratic if it contains terms of $x^{2}$ , with the general form .

$ax^{2} +bx+c=0$

And there are three methods to solve it.

1. By using quadratic formula
2. By factorization method
3. By the method of completing the square.

Here we use the second method , that is the method of factorization.

Under this method, we have to find two numbers such that their sum is the coefficient of $x$ in the equation and their product is the constant term in the equation.

So here by inspection we can see that the numbers $-14,-4$  gives their sum as $-18$ and $-14*-4=56$ .

(or otherwise list the factors of $56$ and choose the pair from it which gives their sum as $-18$)

Solving an equation means finding the values of  , since it contains terms of  , it has two values.

Here, the factors are  $(x-14)(x-4)=x^{2} -18x+56$

Therefore the values of $x$ are $14$ and $4$ .

Hence the answer.

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