factorize x² + 2root2x - 6=0
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Answer:
x²+2√2x-6 = 0
x²+(3√2-√2)x-6 = 0
x²+3√2x-√2x-6 = 0
x(x+3√2)-√2(x-3√2) = 0
(x+3√2)(x-√2) = 0
Either (x+3√2) = 0 OR (x-√2) = 0
Either x = -3√2 OR x = √2
Step-by-step explanation:
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