Question

factorize x2 +3√3 + 6

Answer 1

here is ur answer
hope it helps

Answer 2

Hello dear friend ...

Your Solution Given here ...
☺☺☺✌
_____________________________

Let , the given Polynomial
$f(x) = {x}^{2} + 3 \sqrt{3} x + 6 \\ = > {x}^{2} + 2 \sqrt{3} x + \sqrt{3} x + 6 \\ = > x(x + 2 \sqrt{3} ) + \sqrt{3}(x + 2 \sqrt{3} ) \\ = > (x + \sqrt{3} )(x + 2 \sqrt{3} ) \\ \\ f(x) = 0 \\ \\ (x + \sqrt{3} ) = 0 \: \: \: or \: \: \: (x + 2 \sqrt{3} ) = 0 \\ x = 0 - \sqrt{3} \: \: \: or \: \: \: x = 0 - 2 \sqrt{3} \\ x = - \sqrt{3} \: \: \: or \: \: \: x = - 2 \sqrt{3}$
_____________________________

HOPE it's helps you.
☺☺