factorize (x²-5x+6)(x²+5x+6) -2x²
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Given
factorize (x²-5x+6)(x²+5x+6) -2x²
Solution
Applying identity → a² - b² = (a+b)(a-b)
= (x²-5x+6)(x²+5x+6) -2x²
= [(x² - 5x)² - (6)²] - 2x²
Again, applying identity
(a-b)²= a² + b²- 2ab
= [{(x²)² + (5x)² - 2*x²*5x} - 36] -2x²
= [x⁴ + 25x² - 10x³ - 36] - 2x²
= x⁴ - 10x³ + 25x² - 2x² - 36
= x⁴ - 10x³ + 23x² - 36
Some important identities
- (a+b)² = a² + b² +2ab
- (a-b)² = a² + b² - 2ab
- (a+b)³ = a³ + b³ + 3ab(a+b)
- (a-b)³ = a³ -b³ - 3ab(a-b)
- a² - b² = (a+b)(a-b)
- a³ + b³ = (a+b)(a² - ab +b²)
- a³ - b³ = (a-b)(a² + ab +b²)
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