Question

Factorize:
x²+6√2x+10

Answer 1

Answer:

x2 + 5 root 2 + toote +10

x(x+5root2) + root 2 (x + 5root2)

(x+root 2) (x+5 root 2)

Step-by-step explanation:

Answer 2

Concept :  

Here we factorise it by splitting the middle term.

• To factorise quadratic polynomials of the type ax² + bx + c by middle term splitting ,write b as the sum of two numbers whose product is ac.
• To factorise ax² + bx - c & ax²- bx - c , write b as the difference of two numbers whose product is - ac.

Given : x² + 6√2x + 10

 x² + 6√2x + 10 = x² + √2x + 5√2x + 10

= x(x + √2) + 5√2 (x + √2)

= (x + √2) (x + 5√2)

x² + 6√2x + 10 = (x + √2) (x + 5√2)

Hence, the factorisation of x² + 6√2x + 10 is  (x + √2) (x + 5√2).

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