Factorize:
x²+6√2x+10
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Answer:
x2 + 5 root 2 + toote +10
x(x+5root2) + root 2 (x + 5root2)
(x+root 2) (x+5 root 2)
Step-by-step explanation:
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Concept :
Here we factorise it by splitting the middle term.
- To factorise quadratic polynomials of the type ax² + bx + c by middle term splitting ,write b as the sum of two numbers whose product is ac.
- To factorise ax² + bx - c & ax²- bx - c , write b as the difference of two numbers whose product is - ac.
Given : x² + 6√2x + 10
x² + 6√2x + 10 = x² + √2x + 5√2x + 10
= x(x + √2) + 5√2 (x + √2)
= (x + √2) (x + 5√2)
x² + 6√2x + 10 = (x + √2) (x + 5√2)
Hence, the factorisation of x² + 6√2x + 10 is (x + √2) (x + 5√2).
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