Question

factorize - x² - 6
$x ^{2} - y ^{2} - 2y - 1$


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Answer 1

Answer:

$(x - y - 1)( x + y + 1)$

Step-by-step explanation:

Here are the steps:-

$x {}^{2} - y {}^{2} - 2y - 1$

$= x {}^{2} - (y {}^{2} + 2y + 1)$

$= x {}^{2} - ((y) {}^{2} + 2 \times y \times 1 + (1) {}^{2} )$

$= x {}^{2} - (y + 1) {}^{2}$

$= ( x - (y + 1)) \times (x + (y + 1)$

$= (x - y - 1)( x + y + 1)$

Hope It Helps!!!!!