Question

Factorize; x2 - y2 - 4xz + 4z2

Answer 1

hope it's clear........

Answer 2

Answer:

x²-y²-4xz+4z² = ( x-2z+y )( x-2z-y )

Step-by-step explanation:

Given Expression x²-y²-4xz+4z²

/* Rearranging the terms ,we get

= x²-4xz+4z² - y²

=[ x² - 4 × x × z + (2z)²] - y²

= ( x - 2z )² - y²

/* By algebraic identity,

a²-2ab+b² = (a-b)² */

= [(x-2z)+y][(x-2z)-y]

/* By algebraic identity:

a² - b² = ( a + b )( a - b ) */

= ( x-2z+y )( x-2z-y )

Therefore,

x²-y²-4xz+4z² = ( x-2z+y )( x-2z-y )

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