factorize ;x³-27y³-64z³-36xyz
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Answered by
15
Use the identity
a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c² -ab - bc - ca)
Here a = x, b = (-3)y, c = (-4)z
So given expression is factorised as:
[x +(-3y)+(-4z)][x² + (-3y)² + (-4z)² - x(-3y) - (-3y)(-4z) - (-4z)x
Please complete yourself . It will give you a little practice.
a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c² -ab - bc - ca)
Here a = x, b = (-3)y, c = (-4)z
So given expression is factorised as:
[x +(-3y)+(-4z)][x² + (-3y)² + (-4z)² - x(-3y) - (-3y)(-4z) - (-4z)x
Please complete yourself . It will give you a little practice.
Answered by
2
Step-by-step explanation:
factorize ;x³-27y³-64z³-36xyz
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