Question

factorize x³-2x²y+3xy²-6x³y³

Answer 1

a little mistake is happened in your question.
question should , x³ - 2x²y + 3x⁴y² - 6x³y³
now, x³ - 2x²y + 3x⁴y² - 6x³y³
= x²( x -2y ) + 3x³y²(x -2y )
= (x² + 3x³y²)(x - 2y)
= [x²(1 + 3xy) ] (x - 2y)
= x²(1 + 3xy)(x - 2y)

hence, x²(1 + 3xy)(x - 2y) is the answer of x³ -2x²y + 3x⁴y² - 6x³y³

Answer 2

Step-by-step explanation:

a little mistake is happened in your question. question should, x³ - 2x²y + 3x4y² - 6x³y³ now, x³ - 2x²y + 3x4y² - 6x³y³

= x²(x-2y) + 3x³y²(x-2y) = (x² + 3x³y²)(x - 2y)

= [x²(1 + 3xy) ] (x - 2y) = x²(1 + 3xy)(x - 2y)

hence, x²(1 + 3xy)(x - 2y) is the answer of x³ -2x²y + 3x¹y² - 6x³y³