Factorize:
x³ + 3x² + 3x + 28
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Consider the given equation
x3+3x2+3x+28
=x3+3x2+3x+1+27
=x+13+27
=x+13+33 =x+1+3x+12-3x+1+32 using the identity a3+b3=a+ba2-ab+b2 =[x+4][x2+1+2x-3x-3+9]
=[x+4][x2-x+7]
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